Thanks for the fast replies
thanks to David Beaudoin,Brett Lymn, Sanjiv K. Bhatia,and Matthew Stier.
the original question was :
" > Dear Sun admins,
>
> I am sorry It may be silly question, even I did that before but could
not
> remember how
> anyway, I have file A which contains a list of users id they are part of
their
> home directories in /etc/passwd ( file B )
> I am trying to use nawk to search and get all the lines of file B (
/etc/passwd
> ) with the key of file A
> I was trying to use:
> # cat A | nawk ' { systems ( " grep " $1 )}' B
> that does not give me anything
> remember that A contains 8 digit number in each line
> and B is a copy of the /etc/passwd
>
> Best Regards and thanks in advance
> "
I tried two suggestions :
David Beaudoin suggested using:
cat A | xargs -I {} grep {} /etc/passwd
also Sanjiv K. Bhatia suggested using aloop such as :
#!/bin/ksh
for key in `cat fileA`
do
grep $key fileB
done > outfile
Best Regards
and thanks again
Raed Al-Zoub'i
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